The solution of the differential equation $(x+1) \frac{d y}{d x}-x y=1$, satisfying $y(0)=1$ is
- $\frac{1}{(1+x)}\left(e^x+1\right)=y$
- $\log _e(1+x)+\frac{1}{2}=y$
- $\left(e^x-\frac{1}{2}\right) \frac{1}{x}=y$
- $\frac{1}{(1+x)}\left(2 e^x-1\right)=y$
Solution
Asked in: AP EAMCET 2017 (24 Apr Shift 2)