The solubility product of $\mathrm{Ag}_{2} \mathrm{CrO}_{4}$ is $32 \times 10^{-12}$. What is the…

The solubility product of $\mathrm{Ag}_{2} \mathrm{CrO}_{4}$ is $32 \times 10^{-12}$.
What is the concentration of $\mathrm{CrO}_{4}^{2-}$ ions in that solution (in $\mathrm{g} \mathrm{L}^{-1}$ )
  1. $2 \times 10^{-4}$
  2. $8 \times 10^{-4}$
  3. $8 \times 10^{-8}$
  4. $16 \times 10^{-4}$

Solution

For ternary electrolyte; solubility
$=\left(\frac{\mathrm{K}_{\mathrm{sp}}}{4}ight)^{\frac{1}{3}}=\left(\frac{32 \times 10^{-12}}{4}ight)^{\frac{1}{3}}=2 \times 10^{-4}$ /

Asked in: JEE-TOPICTESTS-CHEMISTRY

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