The solubility product of a sparingly soluble salt A 2 X 3 is 1 . 1 × 10 - 23 . If specific conductance…

The solubility product of a sparingly soluble salt A2X3 is 1.1×10-23. If specific conductance of the solution is 3×10-5Sm-1, the limiting molar conductivity of the solution is x×10-3 S m2 mol-1. The value of x is

Solution

KspA2X3=1.1×10-23=110×10-25

Ksp=2233s5=110×10-25

4×27s5=110×10-25;  S=M=1×10-5

K=3×10-5Sm-1

λm=x×10-3Sm2 mol-1

λm=K×10-3M

=3×10-5×10-31×10-5=3×10-3Sm2 mol-1

Asked in: JEE Main 2022 (28 Jun Shift 1)

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