The solubility of A g C l s with solubility product 1.6 × 10 - 10 in 0.1 M N a C l solution would be

1. $1.26\times {10}^{-5}\mathrm{ }\mathrm{M}$
2. $1.6\times {10}^{-9}\mathrm{ \; M}$
3. $1.6\times {10}^{-11}\mathrm{ }\mathrm{M}$
4. $1.26\times {10}^{-15}\mathrm{ }\mathrm{M}$

Solution

$\therefore {\mathrm{K}}_{\mathrm{s}\mathrm{p}\left(\mathrm{A}\mathrm{g}\mathrm{C}\mathrm{l}\right)}=\mathrm{S}\left(\mathrm{S}+0.1\right)$

$\because \mathrm{S}\ll 0.1$

$\therefore \mathrm{S}+0.1\mathrm{ }\approx 0.1$

$\therefore 1.6\times {10}^{-10}=\mathrm{S}\times 0.1$

$\therefore \mathrm{S}=1.6\times {10}^{-9}\mathrm{ }\mathrm{M}$

Asked in: MHT CET Full Test 8

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