The slope of the tangent to the curve y - x 5 2 = x 1 + x 2 2 at the point (1, 3) is ________.

The slope of the tangent to the curve y-x52=x 1 + x 2 2 at the point (1, 3) is ________.

Solution

2y-x5 dydx-5x4
=11+x22+x 21+x2 2x
Now put x=1, y=3 and dydx=m.
23-1 m-5=1 4+1 4 2
m-5=124
m=5+3=8
dydx=m=8.

Asked in: JEE Advanced 2014 (Paper 1)

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