The slope in Arrhenius plot, is equal to:
- $-\frac{E_{a}}{2.303 R}$
- $\frac{E_{a}}{R}$
- $-\frac{R}{2.303 E_{a}}$
- None of these
Solution
$k=A e^{-E_{a} /(2.303 R T)}$
Taking log on both sides, we get
$\log k=\log A-\frac{E_{a}}{2.303 R T}$
Arrhenius plot a graph between $\log k$ and $\frac{1}{T}$ whose
slope is $\frac{-E_{a}}{2.303 R}$.
Asked in: JEE-TOPICTESTS-CHEMISTRY