The sides of the rectangle of greatest area that can be inscribed in the ellipse $x^2+4 y^2=64$ are :
- $(6 \sqrt{2}, 4 \sqrt{2})$
- $(8 \sqrt{2}, 4 \sqrt{2})$
- $(8 \sqrt{2}, 8 \sqrt{2})$
- $(16 \sqrt{2}, 4 \sqrt{2})$
Solution
Asked in: AP EAMCET 2006
Asked in: AP EAMCET 2006