The SI unit of $\frac{G}{g}$ is $(g=$ acceleration due to gravity, $G=$ constant of gravitation $)$

The SI unit of $\frac{G}{g}$ is $(g=$ acceleration due to gravity, $G=$ constant of gravitation $)$
  1. $\frac{\mathrm{kg}}{\mathrm{m}^{2}}$
  2. $\frac{\mathrm{m}^{2}}{\mathrm{~kg}}$
  3. $\frac{\mathrm{m}}{\mathrm{kg}}$
  4. $\frac{\mathrm{kg}}{\mathrm{m}}$

Solution

$\begin{aligned} & {[\mathrm{G}]=\mathrm{kg}^{-1} \mathrm{~m}^3 \mathrm{~s}^{-2}} \\ & {[\mathrm{~g}]=\mathrm{ms}^{-2}} \\ & \mathrm{G} / \mathrm{g}=\mathrm{m}^2 / \mathrm{kg}\end{aligned}$

Asked in: MHT CET 2020 (15 Oct Shift 2)

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