The shortest wavelength of the spectral lines in the Lyman series of hydrogen spectrum is $915 Ã…$. The longest wavelength of spectral lines in the Balmer series will be _____ $Ã…$.

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Aicharya · Accepted Answer

Shortest, $\frac{\mathrm{hc}}{\lambda}=-13.6\left(\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right)$ $\lambda \downarrow \mathrm{E} \uparrow ; \frac{\mathrm{hc}}{\lambda_0}=-13.6(1)$ Balmer Series :

$\begin{aligned} & \frac{\mathrm{hc}}{\lambda_1}=-13.6\left(\frac{1}{2^2}-\frac{1}{3^2}\right) \\ & \frac{\mathrm{hc}}{\lambda_1}=-13.6\left(\frac{1}{4}-\frac{1}{9}\right) \end{aligned}$ $\begin{aligned} & \frac{\mathrm{hc}}{\lambda_1}=-13.6 \times\left(\frac{5}{36}\right) \\ & \Rightarrow \frac{-13.6 \lambda_0}{\lambda_1}=-13.6 \times \frac{5}{36} \\ & \lambda_1=\frac{\lambda_0 \times 36}{5}=\frac{915 \times 36}{5}=6588\end{aligned}$

The shortest wavelength of the spectral lines in the Lyman series of hydrogen spectrum is $915 Ã…$. The…

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