The shortest wavelength for Lyman series is $912 Å$. The longest wavelength in Paschen series is
The shortest wavelength for Lyman series is $912 Å$. The longest wavelength in Paschen series is
$1216 Å$
$3646 Å$
$18760 Å$
$8208 Å$
Solution
Shortest wavelength in Lyman series is given by
$\begin{aligned}
& \frac{1}{\lambda_{\mathrm{I}}}=\mathrm{R}\left[\frac{1}{1^2}-\frac{1}{\infty}\right]=\mathrm{R} \\
& \therefore \lambda_{\mathrm{I}}=\frac{1}{\mathrm{R}}
\end{aligned}$
The longest wavelength in Paschen series is given by
$\begin{aligned}
& \frac{1}{\lambda_{\mathrm{p}}}=\mathrm{R}\left[\frac{1}{(3)^2}-\frac{1}{(4)^2}\right] \\
& =\mathrm{R}\left[\frac{1}{9}-\frac{1}{16}\right]=\mathrm{R} \cdot \frac{7}{144} \\
& \lambda_{\mathrm{p}}=\frac{144}{7 \mathrm{R}} \\
& \therefore \frac{\lambda_{\mathrm{p}}}{\lambda_{\mathrm{L}}}=\frac{144}{7} \mathrm{R}=\frac{144}{7} \\
& \therefore \lambda_{\mathrm{p}}=\frac{144}{7 \mathrm{R}} \cdot \lambda_{\mathrm{L}}=\frac{144}{7} \times 912=18760 Å
\end{aligned}$