The shortest distance between the lines x - 3 3 = y - 8 - 1 = z - 3 1 and x + 3 - 3 = y + 7 2 = z - 6 4 is

The shortest distance between the lines x-33=y-8-1=z-31 and x+3-3=y+72=z-64 is
  1. 230
  2. 7230
  3. 330
  4. 3

Solution

w→=i^+j^–3k^
p→=3i^-j^+k^
q→=-3i^+2j^+4k^
p→×q→=ijk3-11-324=6i^-15j^+3k^
S.D.=|AB.p×q|p×q=36+225+936+225+9=330

Asked in: JEE Main 2020 (08 Jan Shift 1)

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