The shape of $\mathrm{XeOF}_{4}$ by VSEPR theory is:

Question

Aicharya · Accepted Answer

The shape of $\mathrm{XeOF}_4$ by VSEPR theory is square pyramidal. The central $\mathrm{Xe}$ atom in $\mathrm{XeOF}_4$ has one lone pair of electron and 5 bonding domains. Hence, it undergoes $\mathrm{sp}^3 \mathrm{~d}^2$ hybridization. .

The shape of $\mathrm{XeOF}_{4}$ by VSEPR theory is:

Solution