
The shaded area in the given figure is a solution set for some system of inequalities. The maximum value of…

- 38
- 36
- 33
- 34
Solution

The corner points of the feasible region are $\mathrm{O}(0,0), \mathrm{A}(6,0), \mathrm{B}(6,4), \mathrm{C}(3,7)$ and $\mathrm{D}(0,5)$. $z=4 x+3 y$
At $\mathrm{O}(0,0), \mathrm{z}=4(0)+3(0)=0$ At $A(6,0), z=4(6)+3(0)=24$ At $B(6,4), z=4(6)+3(4)=36$ At $C(3,7), z=4(3)+3(7)=33$ At $D(0,5), z=4(0)+3(5)=15$ $\therefore \quad$ Maximum value of z is 36 .
Asked in: MHT CET 2024 (16 May Shift 2)