The set of three elements having successive atomic numbers and having the ionization energies of 2372, 520…

The set of three elements having successive atomic numbers and having the ionization energies of 2372, 520 and $890 \mathrm{~kJ}$ per mol is
  1. $\mathrm{H}, \mathrm{He}, \mathrm{Li}$
  2. $\mathrm{He}, \mathrm{Li}, \mathrm{Be}$
  3. $\mathrm{Li}, \mathrm{Be}, \mathrm{B}$
  4. $\mathrm{B}, \mathrm{C}, \mathrm{N}$

Solution

He $(\mathrm{Z}=2)$ is a noble gas and has highest I.E. The I.E. of $\operatorname{Be}(Z=4)$ is more than that of $\mathrm{Li}(\mathrm{Z}=3)$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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