The set of solutions satisfying both $x^2+5 x+6 \geq 0$ and $x^2+3 x-4

Question

The set of solutions satisfying both $x^2+5 x+6 \geq 0$ and $x^2+3 x-4 < 0$ is

Aicharya · Accepted Answer

Given, $x^2+5 x+6 \geq 0$ and $x^2+3 x-4 < 0$ $ \begin{aligned} & \Rightarrow x \in(-\infty,-3] \cup[-2, \infty) 	ext { and } x \in(-4,1) \ & \end{aligned} $ Common condition is $ x \in(-4,-3] \cup[-2,1) $

The set of solutions satisfying both $x^2+5 x+6 \geq 0$ and $x^2+3 x-4 < 0$ is

Solution