The set of all $x$ for which $\sin x \leq x$ is

1. $\left(0, \frac{\pi}{2}\right)$
2. $\left(-\frac{\pi}{2}, \pi\right)$
3. $\left(\frac{-\pi}{2}, 0\right)$
4. $\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$

Solution

Clearly, $\sin x \leq x$ for $x \in\left(0, \frac{\pi}{2}\right)$

Asked in: AP EAMCET 2022 (07 Jul Shift 1)

Practice more Trigonometric Equations questions on Aicharya