The self-inductance of a long solenoid of cross-sectional area $\mathrm{A}$, length $l$ and $\mathrm{n}$…

The self-inductance of a long solenoid of cross-sectional area $\mathrm{A}$, length $l$ and $\mathrm{n}$ turns'per unit length is given by
  1. $\mu_0 n \mathrm{Al}$
  2. $\mu_0 n^2 \mathrm{Al}$
  3. $\mu_0 n^2 \mathrm{~A}^2 l$
  4. $\mu_0 n^2 \pi \mathrm{A}^2 l$

Solution

Magnetic flux, $\phi_{\mathrm{B}}=\mathrm{B} . \mathrm{A}$ for solenoid, $\mathrm{B}=\mu_0 \mathrm{n}$ I $ \phi_{\mathrm{B}}=\mu_0 \mathrm{nIA} $ The total magnetic flux associates with the solenoid $ \begin{aligned} & \phi_{\mathrm{B}}=\mu_0 \mathrm{nIA} \times \mathrm{N} \\ & \mathrm{N}=\mathrm{nL} \\ & =\mu \mathrm{n}^2 \mathrm{IAL} \end{aligned} $

Asked in: AP EAMCET 2023 (18 May Shift 2)

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