The roots of the equation \(\left|x^2-x-6\right|=x+2\) are

The roots of the equation \(\left|x^2-x-6\right|=x+2\) are
  1. \(-2,1,4\)
  2. \(0,2,4\)
  3. \(0,1,4\)
  4. \(-2,2,4\)

Solution

Given, \(\left|x^2-x-6\right|=x+2\) \(\begin{array}{ll} \Rightarrow & x^2-x-6=x+2 \\ \text {Or } & x^2-x-6=-x-2 \\ \Rightarrow & x^2-2 x-8=0 \text { or } x^2=4 \\ \Rightarrow & (x=-2,4) \text { or }(x= \pm 2) \Rightarrow x=\{-2,2,4\} \end{array}\)

Asked in: AP EAMCET 2020 (17 Sep Shift 1)

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