The rms velocity of a gas molecule of mass ' $m$ ' at a given temperature is proportional to
The rms velocity of a gas molecule of mass ' $m$ ' at a given temperature is proportional to
$\mathrm{m}^{\circ}$
m
$\sqrt{m}$
$\frac{1}{\sqrt{m}}$
Solution
The rms velocity of a gas molecule of mass $m$ is
$\mathrm{v}_{\mathrm{rms}}=\sqrt{\frac{3 \mathrm{KT}}{\mathrm{m}}} \Rightarrow \mathrm{v}_{\mathrm{rms}} \propto \frac{1}{\sqrt{\mathrm{~m}}}$