The rms value of potential difference $V$ shown in the figure is

Question

Aicharya · Accepted Answer

$V_{\mathrm{rms}}=\left[\frac{1}{T} \int_0^{T / 2} V_0^2 d tight]^{1 / 2}$ $\begin{aligned} & =\left[\frac{V_0^2}{T}[t]_0^{T / 2}ight]^{1 / 2} \ & =\left[\frac{V_0^2}{T}\left(\frac{T}{2}ight)ight]^{1 / 2} \ V_{\mathrm{rms}} & =\left[\frac{V_0^2}{2}ight]^{1 / 2} \ V_{\mathrm{mms}} & =\frac{V_0}{\sqrt{2}} \end{aligned}$ :

The rms value of potential difference $V$ shown in the figure is

Solution