The rms speed of oxygen molecule at a certain temperature is $600 \mathrm{~ms}^{-1}$. If the temperature is…
- $120 \mathrm{~ms}^{-1}$
- $150 \mathrm{~ms}^{-1}$
- $1200 \mathrm{~ms}^{-1}$
- $600 \mathrm{~ms}^{-1}$
Solution

At temperature, $T_2=2 \pi T_1$, due to dissociation

Dividing Eq. (i) by Eq. (ii), we get $\Rightarrow \quad \frac{v}{600}=2 \quad \Rightarrow v=1200 \mathrm{~ms}^{-1}$
Asked in: MHT CET Full Test 7