The rms speed of a gas molecule is ' $\mathrm{V}$ ' at pressure ' $\mathrm{P}$ '. If the pressure is…
The rms speed of a gas molecule is ' $\mathrm{V}$ ' at pressure ' $\mathrm{P}$ '. If the pressure is increased by two time, then the rms speed of the gas molecule at the same temperature will be
$\mathrm{V}$
$\sqrt{2} \mathrm{~V}$
$\frac{\mathrm{V}}{3}$
$\frac{\mathrm{V}}{2}$
Solution
Since temperature remains constant, there will be no change in r.m.s velocity.