The resultant of two vectors $\vec{A}$ and $\vec{B}$ is perpendicular to $\vec{A}$ and its magnitude is half that of $\vec{B}$. The angle between vectors $\vec{A}$ and $\vec{B}$ is ______ $\circ$.

Question

Aicharya · Accepted Answer

$\begin{aligned}& \mathrm{B} \cos 	heta=\frac{\mathrm{B}}{2} \ & \Rightarrow 	heta=60^{\circ}\end{aligned}$ So, angle between $\overrightarrow{\mathrm{A}} \& \overrightarrow{\mathrm{B}}$ is $90^{\circ}+60^{\circ}=150^{\circ}$

The resultant of two vectors $\vec{A}$ and $\vec{B}$ is perpendicular to $\vec{A}$ and its magnitude is half…

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