The resultant gate and its Boolean expression in the given circuit is

The resultant gate and its Boolean expression in the given circuit is
  1. $\mathrm{NOR}, \overline{\mathrm{A}+\mathrm{B}}$
  2. $AND, A.B$
  3. $\text { OR, A } + B$
  4. $NAND, \overline{\mathrm{AB}}$

Solution

Truth table: \begin{array}{|l|l|l|l|l|} \hline A & B & C & D & Y \\ \hline 0 & 0 & 1 & 1 & 0 \\ \hline 0 & 1 & 1 & 0 & 0 \\ \hline 1 & 0 & 0 & 1 & 0 \\ \hline 1 & 1 & 0 & 0 & 1 \\ \hline \end{array} This is truth table of AND gate. $\therefore \mathrm{Y}=\mathrm{A} \cdot \mathrm{B}$

Asked in: MHT CET 2021 (23 Sep Shift 2)

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