The resultant capacity between points $\mathrm{A}$ and $\mathrm{B}$ in the given circuit is

The resultant capacity between points $\mathrm{A}$ and $\mathrm{B}$ in the given circuit is
  1. $\mathrm{C}$
  2. $\frac{\mathrm{C}}{3}$
  3. $3 \mathrm{C}$
  4. $2 \mathrm{C}$

Solution

$\mathrm{C}_1$ and $\mathrm{C}_2$ are in parallel, their equivalent capacitance $\mathrm{C}_7=2 \mathrm{C}$. $\mathrm{C}_7$ and $\mathrm{C}_3$ are in series, their equivalent capacitance is $\mathrm{C}_8=\mathrm{C}$. $\mathrm{C}_8$ and $\mathrm{C}_4$ are in parallel, their equivalent capacitance is $\mathrm{C}_9=2 \mathrm{C}$. $\mathrm{C}_9$ and $\mathrm{C}_5$ are in series, their equivalent capacitance $\mathrm{C}_{10}=\mathrm{C}$. $\mathrm{C}_{10}$ and $\mathrm{C}_6$ are in parallel, their equivalent capacitance is $3 \mathrm{C}$ Hence equivalent capacitance between $\mathrm{A}$ and $\mathrm{B}$ is $3 \mathrm{C}$

Asked in: MHT CET 2021 (21 Sep Shift 1)

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