The resistances in the left and right gap of a metre bridge are $40 \Omega$ and $60 \Omega$ respectively. When the bridge is balanced, the distance of the null point from the centre of the wire towards left is

Question

Aicharya · Accepted Answer

From the given data, $\begin{aligned} & \frac{40}{60}=\frac{50-l}{50+l} \ & 2000+40 l=3000-60 l \ & 100 l=1000 \ 	herefore \quad & l=10 \mathrm{~cm} \end{aligned}$

The resistances in the left and right gap of a metre bridge are $40 \Omega$ and $60 \Omega$ respectively.…

Solution