The resistance of $1 \mathrm{~N}$ solution of acetic acic is $250 \mathrm{ohm}$, when measured in a cell of…

The resistance of $1 \mathrm{~N}$ solution of acetic acic is $250 \mathrm{ohm}$, when measured in a cell of cell constant $1.15 \mathrm{~cm}^{-1}$. The equivalent conductance (in $\mathrm{ohm}^{-1} \mathrm{~cm}^{2}$ equiv $^{-1}$ ) of $1 \mathrm{~N}$ acetic acid will be
  1. $4.6$
  2. $9.2$
  3. $18.4$
  4. $0.023$

Solution

$\begin{aligned} \kappa &=\frac{\text { Cell constant }}{\mathrm{R}}=\frac{1.15}{250} \\ & \Lambda_{\mathrm{eq}}=\frac{1.15}{250} \times \frac{1000}{1}=4.6 \end{aligned}$ ~

Asked in: JEE-TOPICTESTS-CHEMISTRY

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