The resistance of decimolar solution of NaCl is 30 ohms. Calculate the conductivity of solution if the cell…
The resistance of decimolar solution of NaCl is 30 ohms. Calculate the conductivity of solution if the cell constant is $0.33 \mathrm{~cm}^{-1}$.
- $0.025 \Omega^{-1} \mathrm{~cm}^{-1}$
- $0.035 \Omega^{-1} \mathrm{~cm}^{-1}$
- $0.011 \Omega^{-1} \mathrm{~cm}^{-1}$
- $0.029 \Omega^{-1} \mathrm{~cm}^{-1}$
Solution
$\begin{aligned} \text { Conductivity } & =\frac{\text { cell constant }}{\text { Resistance }} \\ & =\frac{0.33 \mathrm{~cm}^{-1}}{30 \Omega} \\ & =0.011 \Omega^{-1} \mathrm{~cm}^{-1}\end{aligned}$
Asked in: MHT CET 2024 (02 May Shift 1)
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