The resistance of a conductivity cell containing $0.001 \mathrm{M}$ KC1 solution at $300 \mathrm{~K}$ is…

The resistance of a conductivity cell containing $0.001 \mathrm{M}$ KC1 solution at $300 \mathrm{~K}$ is $150 \Omega$. What is the cell constant if conductivity of $\mathrm{KCl}$ solution is $1.5 \times 10^{-} \Omega^{-1} \mathrm{~cm}^{-1}$
  1. $0.112 \mathrm{~cm}^{-1}$
  2. $0.225 \mathrm{~cm}^{-1}$
  3. $0.337 \mathrm{~cm}^{-1}$
  4. $0.450 \mathrm{~cm}^{-1}$

Solution

We know $\mathrm{K}=\frac{1}{\mathrm{R}}=\left(\frac{\mathrm{L}}{\mathrm{A}}\right)$ $\begin{aligned} & 1.5 \times 10^{-3}=\frac{1}{150} \times\left(\frac{L}{A}\right) \\ & \frac{L}{A}=0.225 \mathrm{~cm}^{-1}\end{aligned}$

Asked in: MHT CET 2022 (07 Aug Shift 2)

Practice more Electrochemistry questions on Aicharya