The resistance of a bulb filament is $100 \Omega$ at a temperature of $100^{\circ} \mathrm{C}$. If its…

The resistance of a bulb filament is $100 \Omega$ at a temperature of $100^{\circ} \mathrm{C}$. If its temperature coefficient of resistance be $0.005$ per ${ }^{\circ} \mathrm{C}$, its resistance will become $200 \Omega$ at a temperature of
  1. $200^{\circ} \mathrm{C}$
  2. $300^{\circ} \mathrm{C}$
  3. $400^{\circ} \mathrm{C}$
  4. $500^{\circ} \mathrm{C}$

Solution

$200=100[1+(0.005 \times \Delta t)]$ $T-100=200$ $\mathrm{T}=300^{\circ} \mathrm{C}$

Asked in: JEE Main 2006

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