The relationship between the radius (r) of the atom and the edge length $(a)$ of the cubic close packing…
- $\mathrm{r}=\frac{\sqrt{3}}{4} a$
- $\mathrm{r}=\frac{a}{2 \sqrt{2}}$
- $\mathrm{r}=\frac{a}{\sqrt{2}}$
- $\mathrm{r}=\frac{a}{2 \sqrt{3}}$
Solution
Asked in: AP EAMCET 2017 (25 Apr Shift 2)