The relation between time $t$ and distance $\mathrm{x}$ is $\mathrm{t}=a \mathrm{x}^2+\mathrm{bx}$ where…
The relation between time $t$ and distance $\mathrm{x}$ is $\mathrm{t}=a \mathrm{x}^2+\mathrm{bx}$ where $\mathrm{a}$ and $\mathrm{b}$ are constants. The acceleration is
$-2 a b v^2$
$2 b v^3$
$-2 a v^3$
$2 a v^2$
Solution
$
t=a x^2+b x
$
by differentiating acceleration $=-2 a v^3$