The relation between efficiency $\eta$ of a heat engine and the coefficient of performance $\alpha$ of a…

The relation between efficiency $\eta$ of a heat engine and the coefficient of performance $\alpha$ of a refrigerator is
  1. $\eta=\frac{1}{1-\alpha}$
  2. $\eta=\frac{1}{1+\alpha}$
  3. $\eta = 1 + \alpha$
  4. $\eta = 1 - \alpha$

Solution

$\eta=\frac{1}{1+\alpha}$. This is the required relation.

Asked in: AP EAMCET 2015

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