The refractive index of the material of a glass prism is $\sqrt{3}$. The angle of minimum deviation is equal to the angle of the prism. What is the angle of the prism?

Question

Aicharya · Accepted Answer

$\mu=\frac{\sin \left(\frac{A+\delta_{\min }}{2}\right)}{\sin \frac{A}{2}}$
Given $\delta_{\min }=\mathrm{A}$
$\begin{aligned}
& \sqrt{3}=\frac{\sin A}{\sin \frac{A}{2}}=\frac{2 \sin \frac{A}{2} \cos \frac{A}{2}}{\sin \frac{A}{2}} \\ & \cos \frac{A}{2}=\frac{\sqrt{3}}{2} \\ & A=60^{\circ}
\end{aligned}$

The refractive index of the material of a glass prism is $\sqrt{3}$. The angle of minimum deviation is equal…

Solution