
The reagent $P$ used for the reaction is

- $\mathrm{Zn}-\mathrm{Hg} / \mathrm{HCl}$
- $\mathrm{HCl} / \mathrm{SnCl}_2$
- $\mathrm{Br}_2 / \mathrm{NaOH}$
- $\mathrm{ZnCl} / \mathrm{HCl}$
Solution
Asked in: JEE-TOPICTESTS-CHEMISTRY

Asked in: JEE-TOPICTESTS-CHEMISTRY