The reaction of aryl halide with sodium metal in dry ether to give biphenyl is known as
- Swartz reaction
- Wurtz reaction
- Fittig reaction
- Wurtz-fittig reaction
Solution
The reaction of aryl halides with sodium metal in dry ether to form biphenyl constitutes the Fittig reaction. This transformation produces biaryl compounds through the general reaction $\mathrm{Ar-X + 2Na + X-Ar \rightarrow Ar-Ar + 2NaX}$.
The Swartz reaction employs metallic fluorides to synthesize alkyl fluorides and does not involve aryl halides or biphenyl formation. The Wurtz reaction couples two alkyl halides to form alkanes: $\mathrm{R-X + 2Na + X-R \rightarrow R-R + 2NaX}$.
Although the Wurtz-Fittig reaction involves aryl halides, it requires an alkyl halide co-reactant and produces alkylarenes rather than biaryls.
Since the transformation specifically couples two aryl halide molecules to form a biaryl compound, it corresponds exclusively to the Fittig reaction.
Asked in: MHT CET 2025 (23 April Shift 1)