The reaction, $3 \mathrm{ClO}^{-} \rightarrow \mathrm{ClO}_3^{-}+2 \mathrm{Cl}^{-}$occurs in two steps: i.…

The reaction, $3 \mathrm{ClO}^{-} \rightarrow \mathrm{ClO}_3^{-}+2 \mathrm{Cl}^{-}$occurs in two steps: i. $\quad 2 \mathrm{ClO}^{-} \rightarrow \mathrm{ClO}_2^{-}+\mathrm{Cl}^{-}$ ii. $\quad \mathrm{ClO}_2^{-}+\mathrm{ClO}^{-} \rightarrow \mathrm{ClO}_3^{-}+\mathrm{Cl}^{-}$, the reaction intermediate is:
  1. $\mathrm{Cl}^{-}$
  2. $\mathrm{ClO}_2^{-}$
  3. $\mathrm{ClO}_3^{-}$
  4. $\mathrm{ClO}^{-}$

Solution

$\mathrm{ClO}_2^{-}$is produced in step (i) and consumed in step (ii). Therefore, $\mathrm{ClO}_2^{-}$is the reaction intermediate.

Asked in: MHT CET 2023 (10 May Shift 1)

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