The reaction conditions leading to the best yields of $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}$ are:

The reaction conditions leading to the best yields of $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}$ are:
  1. $\mathrm{C}_{2} \mathrm{H}_{6}($ excess $)+\mathrm{Cl}_{2} \stackrel{\text { UV light }}{\longrightarrow}$
  2. $\mathrm{C}_{2} \mathrm{H}_{6}+\mathrm{Cl}_{2} \frac{\text { dark }}{\text { room temperature }}$
  3. $\mathrm{C}_{2} \mathrm{H}_{6}+\mathrm{Cl}_{2}$ (excess) $\stackrel{\text { UV light }}{\longrightarrow}$
  4. $\mathrm{C}_{2} \mathrm{H}_{6}+\mathrm{Cl}_{2} \stackrel{\text { UV light }}{\longrightarrow}$

Solution

$\mathrm{C}_{2} \mathrm{H}_{6}($ excess $)+\mathrm{Cl}_{2} \stackrel{\text { UV light }}{\longrightarrow} \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}+\mathrm{HCl}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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