The ratio of work done by an ideal rigid diatomic gas to the heat supplied by the gas in an isobaric process…

The ratio of work done by an ideal rigid diatomic gas to the heat supplied by the gas in an isobaric process is
  1. $\frac{3}{7}$
  2. $\frac{2}{7}$
  3. $\frac{4}{7}$
  4. $\frac{5}{7}$

Solution

For an isobaric process, $\begin{array}{ll} & \frac{\Delta \mathrm{Q}}{\Delta \mathrm{U}}=\frac{\mathrm{C}_{\mathrm{p}}}{\mathrm{C}_{\mathrm{v}}}=\frac{7}{5} \\ \therefore \quad & \frac{\Delta \mathrm{Q}-\Delta \mathrm{U}}{\Delta \mathrm{Q}}=\frac{7-5}{7} \quad \text { (Applying dividendo) } \\ \therefore \quad & \frac{\mathrm{W}}{\Delta \mathrm{Q}}=\frac{2}{7} \end{array}$

Asked in: MHT CET 2024 (15 May Shift 1)

Practice more Thermodynamics questions on Aicharya