The ratio of the dimensions of Planck's constant and that of the moment of inertia is the dimensions of
- time
- frequency
- angular momentum
- velocity
Solution
[As $\left.\frac{\mathrm{nh}}{2 \pi}=\mathrm{I} \omega\right]$
$
=\frac{2 \pi \mathrm{I}(2 \pi \mathrm{f})}{\mathrm{nI}}=\left(\frac{4 \pi^{2}}{\mathrm{n}} \cdot \mathrm{f}\right)=\left[\mathrm{T}^{-1}\right]
$
Asked in: JEE Mains - Units and Dimensions - Test 3