The ratio of the de-Broglie wavelengths for the electron and proton moving with the same velocity is…
The ratio of the de-Broglie wavelengths for the electron and proton moving with the same velocity is $\left(m_p\right.$-mass of proton, $m_e$-mass of electron)
$m_p: m_e$
$m_p^2: m_e^2$
$m_e: m_p$
$m_e^2: m_p^2$
Solution
As, we know that de-Broglie wave lengths
$\lambda=\frac{h}{m v} \Rightarrow \lambda \propto \frac{1}{m} \text { So, } \frac{\lambda_e}{\lambda_p}=\frac{m_p}{m_e}$