The ratio of the areas of the electron orbits for the second excited state to the first excited state for the hydrogen atom is

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Aicharya · Accepted Answer

$\begin{aligned} & r_n \propto n^2 \Rightarrow A_n \propto n^4 	ext { where, } A_n=	ext { area } \ 	herefore \quad & \frac{A_3}{A_2}=\left(\frac{3}{2}ight)^4=\frac{81}{16}\end{aligned}$

The ratio of the areas of the electron orbits for the second excited state to the first excited state for…

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