The ratio of the areas of the concentric circles $x^2+y^2-$ $6 x+12 y+15=0$ and $x^2+y^2-6 x+12 y-15=0$ is
The ratio of the areas of the concentric circles $x^2+y^2-$ $6 x+12 y+15=0$ and $x^2+y^2-6 x+12 y-15=0$ is
- $1: \sqrt{2}$
- $1: \sqrt{3}$
- $1: 2$
- $1: 4$
Solution
Given $C_1=x^2+y^2-6 x+12 y+15=0$
and $C_2=x^2+y^2-6 x+12 y-15=0$
$\Rightarrow r_1=\sqrt{30}$ and $r_2=\sqrt{60}$
Now ratio of their areas $=1: 2$
Asked in: AP EAMCET 2022 (08 Jul Shift 1)
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