The ratio of rates of diffusion of gases \(A\) and \(B\) is \(1: 0.707\). If the molecular weight of \(B\)…
The ratio of rates of diffusion of gases \(A\) and \(B\) is \(1: 0.707\). If the molecular weight of \(B\) is 32 , the molecular weight of \(A\) is
- 2
- 64
- 16
- 8
Solution
Rate of diffusion is inversely proportional to the square root of molecular weight.
\(\begin{aligned}
\text {i.e. } \quad R & \propto \frac{1}{\sqrt{M}} \\
\therefore \quad \frac{R_A}{R_B} & =\sqrt{\frac{M_B}{M_A}} \\
\frac{1}{0.707} & =\sqrt{\frac{32}{M_A}} \\
\frac{1}{0.499849} & =\frac{32}{M_A} \\
M_A & =15.99 \approx 16
\end{aligned}\)
Asked in: AP EAMCET 2019 (23 Apr Shift 1)
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