The ratio of radii of $3^{ ext {rd }}$ and $6^{ ext {th }}$ Bohr's orbit in a hydrogen atom is

Question

The ratio of radii of $3^{	ext {rd }}$ and $6^{	ext {th }}$ Bohr's orbit in a hydrogen atom is

Aicharya · Accepted Answer

We have, $\frac{\mathrm{r}_3}{\mathrm{r}_6}=\frac{3^2}{6^2}=\frac{9}{36}=0.25 \quad\left[\because \mathrm{r}_{\mathrm{n}} \propto \mathrm{n}^2\right]$

The ratio of radii of $3^{\text {rd }}$ and $6^{\text {th }}$ Bohr's orbit in a hydrogen atom is

Solution