The ratio of maximum to minimum wavelength in Balmer series hydrogen atom is
- 36:5
- 3:4
- 9:5
- 5:9
Solution
Minimum wavelength,
Dividing Eq. (2) by Eq. (1)
$\frac{\lambda}{\lambda^{\prime}}=\frac{9}{5}$Asked in: MHT CET 2021 (23 Sep Shift 1)
Minimum wavelength,
Dividing Eq. (2) by Eq. (1)
$\frac{\lambda}{\lambda^{\prime}}=\frac{9}{5}$