The ratio of maximum and minimum intensities in an interference pattern is $36: 1$. The ratio of the amplitude of the two interfering waves will be

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Aicharya · Accepted Answer

$\frac{I_{\max }}{I_{\min }}=\frac{36}{1}$ We know, $I_{\max }=\left(a+a_2ight)^2$ $ \begin{array}{rlrl} I_{\min } & =\left(a_1-a_2ight)^2 \ & & \frac{\left(a_1+a_2ight)^2}{\left(a_1-a_2ight)^2} & =\frac{36}{1} \Rightarrow \frac{a_1+a_2}{a_1-a_2}=\frac{6}{1} \ \Rightarrow & & a_1+a_2 & =6 a_1-6 a_2 \ \Rightarrow & & 5 a_1 & =7 a_2 \end{array} $ $	herefore$ The ratio of amplitude, $\frac{a_1}{a_2}=\frac{7}{5}$

The ratio of maximum and minimum intensities in an interference pattern is $36: 1$. The ratio of the…

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