The ratio of kinetic energy and total energy of an electron in Bohr orbit of hydrogen-like species is
The ratio of kinetic energy and total energy of an electron in Bohr orbit of hydrogen-like species is
- \(1 / 2\)
- \(1 / 4\)
- \(-1\)
- \(-1 / 2\)
Solution
The ratio \(\mathrm{KE} / E=-1\)
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Asked in: JEE-TOPICTESTS-CHEMISTRY
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