The ratio of intensities of two waves producing interference is $9: 4$, then the ratio of the resultant maximum and minimum intensities will be $\left(\cos \frac{\pi}{3}=\frac{1}{2}\right)$

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Aicharya · Accepted Answer

$\frac{I_{1}}{I_{2}}=\frac{9}{4}$ $	herefore \frac{a_{1}}{a_{2}}=\frac{3}{2}$ $\frac{a_{1}+a_{2}}{a_{1}-a_{2}}=\frac{3+2}{3-2}=\frac{5}{1}$ $	herefore \frac{\left(a_{1}+a_{2}ight)^{2}}{\left(a_{1}-a_{2}ight)^{2}}=\frac{25}{1}$

The ratio of intensities of two waves producing interference is $9: 4$, then the ratio of the resultant…

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