The ratio of effective number of atoms in a unit cell of fcc and bcc lattices is
The ratio of effective number of atoms in a unit cell of fcc and bcc lattices is
$1: 2$
$4: 1$
$1: 4$
$2: 1$
Solution
The face-centered cubic (fcc) contains 4 atoms per unit cell while bccc (body-centered cubic) lattices contains 2 atoms per unit cell.
$\frac{\text { Effective number of atoms in fcc }}{\text { Effective number of atoms in bcc }}=\frac{4}{2}=2: 1$